12 –³–Ό‚³‚ρ
11^2+y^2=12^2+z^2
11^2+(y +z/cosƒ³)^2=(12 +ztanƒ³)^2
2yz/cosƒ³+z^2/cos^2ƒ³=24ztanƒ³+z^2/tan^2ƒ³
y=(cosƒ³/2){24tanƒ³+(1/tan^2ƒ³-1/cos^2ƒ³)z}
12cosƒ³/tanƒ³=‚ˆA(cosƒ³/2)(1/tan^2ƒ³-1/cos^2ƒ³)121+(h+kz)^2=144+z^2
(k^2-1)z^2+2hkz+h^2-23=0
z0=(-hk+γ{(hk)^2+23(k^2-1)})/(k^2-1)
y=γ(z0^2-23)